In a pedigree chart where two Type AB parents have four children, how many children would be expected to have type AB blood?

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To understand the expected outcome of the blood types of children from two Type AB parents, it's essential to look at the genetics of blood type inheritance. Type AB blood means that each parent has both A and B alleles (genotype I^A I^B).

When two parents both have this genotype, the possible combinations for their offspring's blood type can be determined through a Punnett square. The parents can pass on either an A allele or a B allele, leading to the following potential genotypes for their children:

  1. I^A I^A (Type A)

  2. I^A I^B (Type AB)

  3. I^B I^B (Type B)

According to the Punnett square analysis:

  • The parents can produce children with the following combinations:

  • I^A from the first parent and I^A from the second = Type A.

  • I^A from the first parent and I^B from the second = Type AB.

  • I^B from the first parent and I^A from the second = Type AB.

  • I^B from the first parent and I^B from the second = Type B.

In this situation, the outcome results in three possible blood

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